3.885 \(\int \frac {1}{x^3 (a+b x^6)^2 \sqrt {c+d x^6}} \, dx\)

Optimal. Leaf size=64 \[ -\frac {\sqrt {\frac {d x^6}{c}+1} F_1\left (-\frac {1}{3};2,\frac {1}{2};\frac {2}{3};-\frac {b x^6}{a},-\frac {d x^6}{c}\right )}{2 a^2 x^2 \sqrt {c+d x^6}} \]

[Out]

-1/2*AppellF1(-1/3,2,1/2,2/3,-b*x^6/a,-d*x^6/c)*(1+d*x^6/c)^(1/2)/a^2/x^2/(d*x^6+c)^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 0.09, antiderivative size = 64, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {465, 511, 510} \[ -\frac {\sqrt {\frac {d x^6}{c}+1} F_1\left (-\frac {1}{3};2,\frac {1}{2};\frac {2}{3};-\frac {b x^6}{a},-\frac {d x^6}{c}\right )}{2 a^2 x^2 \sqrt {c+d x^6}} \]

Antiderivative was successfully verified.

[In]

Int[1/(x^3*(a + b*x^6)^2*Sqrt[c + d*x^6]),x]

[Out]

-(Sqrt[1 + (d*x^6)/c]*AppellF1[-1/3, 2, 1/2, 2/3, -((b*x^6)/a), -((d*x^6)/c)])/(2*a^2*x^2*Sqrt[c + d*x^6])

Rule 465

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> With[{k = GCD[m + 1,
n]}, Dist[1/k, Subst[Int[x^((m + 1)/k - 1)*(a + b*x^(n/k))^p*(c + d*x^(n/k))^q, x], x, x^k], x] /; k != 1] /;
FreeQ[{a, b, c, d, p, q}, x] && NeQ[b*c - a*d, 0] && IGtQ[n, 0] && IntegerQ[m]

Rule 510

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[(a^p*c^q
*(e*x)^(m + 1)*AppellF1[(m + 1)/n, -p, -q, 1 + (m + 1)/n, -((b*x^n)/a), -((d*x^n)/c)])/(e*(m + 1)), x] /; Free
Q[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] && (IntegerQ[p] || GtQ[a
, 0]) && (IntegerQ[q] || GtQ[c, 0])

Rule 511

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Dist[(a^IntPa
rt[p]*(a + b*x^n)^FracPart[p])/(1 + (b*x^n)/a)^FracPart[p], Int[(e*x)^m*(1 + (b*x^n)/a)^p*(c + d*x^n)^q, x], x
] /; FreeQ[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] &&  !(IntegerQ[
p] || GtQ[a, 0])

Rubi steps

\begin {align*} \int \frac {1}{x^3 \left (a+b x^6\right )^2 \sqrt {c+d x^6}} \, dx &=\frac {1}{2} \operatorname {Subst}\left (\int \frac {1}{x^2 \left (a+b x^3\right )^2 \sqrt {c+d x^3}} \, dx,x,x^2\right )\\ &=\frac {\sqrt {1+\frac {d x^6}{c}} \operatorname {Subst}\left (\int \frac {1}{x^2 \left (a+b x^3\right )^2 \sqrt {1+\frac {d x^3}{c}}} \, dx,x,x^2\right )}{2 \sqrt {c+d x^6}}\\ &=-\frac {\sqrt {1+\frac {d x^6}{c}} F_1\left (-\frac {1}{3};2,\frac {1}{2};\frac {2}{3};-\frac {b x^6}{a},-\frac {d x^6}{c}\right )}{2 a^2 x^2 \sqrt {c+d x^6}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [B]  time = 0.37, size = 226, normalized size = 3.53 \[ \frac {-5 x^6 \left (a+b x^6\right ) \sqrt {\frac {d x^6}{c}+1} \left (3 a^2 d^2-15 a b c d+8 b^2 c^2\right ) F_1\left (\frac {2}{3};\frac {1}{2},1;\frac {5}{3};-\frac {d x^6}{c},-\frac {b x^6}{a}\right )+20 a \left (c+d x^6\right ) \left (3 a^2 d-3 a b \left (c-d x^6\right )-4 b^2 c x^6\right )+2 b d x^{12} \left (a+b x^6\right ) \sqrt {\frac {d x^6}{c}+1} (4 b c-3 a d) F_1\left (\frac {5}{3};\frac {1}{2},1;\frac {8}{3};-\frac {d x^6}{c},-\frac {b x^6}{a}\right )}{120 a^3 c x^2 \left (a+b x^6\right ) \sqrt {c+d x^6} (b c-a d)} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[1/(x^3*(a + b*x^6)^2*Sqrt[c + d*x^6]),x]

[Out]

(20*a*(c + d*x^6)*(3*a^2*d - 4*b^2*c*x^6 - 3*a*b*(c - d*x^6)) - 5*(8*b^2*c^2 - 15*a*b*c*d + 3*a^2*d^2)*x^6*(a
+ b*x^6)*Sqrt[1 + (d*x^6)/c]*AppellF1[2/3, 1/2, 1, 5/3, -((d*x^6)/c), -((b*x^6)/a)] + 2*b*d*(4*b*c - 3*a*d)*x^
12*(a + b*x^6)*Sqrt[1 + (d*x^6)/c]*AppellF1[5/3, 1/2, 1, 8/3, -((d*x^6)/c), -((b*x^6)/a)])/(120*a^3*c*(b*c - a
*d)*x^2*(a + b*x^6)*Sqrt[c + d*x^6])

________________________________________________________________________________________

fricas [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/(b*x^6+a)^2/(d*x^6+c)^(1/2),x, algorithm="fricas")

[Out]

Timed out

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (b x^{6} + a\right )}^{2} \sqrt {d x^{6} + c} x^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/(b*x^6+a)^2/(d*x^6+c)^(1/2),x, algorithm="giac")

[Out]

integrate(1/((b*x^6 + a)^2*sqrt(d*x^6 + c)*x^3), x)

________________________________________________________________________________________

maple [F]  time = 0.46, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (b \,x^{6}+a \right )^{2} \sqrt {d \,x^{6}+c}\, x^{3}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^3/(b*x^6+a)^2/(d*x^6+c)^(1/2),x)

[Out]

int(1/x^3/(b*x^6+a)^2/(d*x^6+c)^(1/2),x)

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (b x^{6} + a\right )}^{2} \sqrt {d x^{6} + c} x^{3}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^3/(b*x^6+a)^2/(d*x^6+c)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/((b*x^6 + a)^2*sqrt(d*x^6 + c)*x^3), x)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {1}{x^3\,{\left (b\,x^6+a\right )}^2\,\sqrt {d\,x^6+c}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^3*(a + b*x^6)^2*(c + d*x^6)^(1/2)),x)

[Out]

int(1/(x^3*(a + b*x^6)^2*(c + d*x^6)^(1/2)), x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^{3} \left (a + b x^{6}\right )^{2} \sqrt {c + d x^{6}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**3/(b*x**6+a)**2/(d*x**6+c)**(1/2),x)

[Out]

Integral(1/(x**3*(a + b*x**6)**2*sqrt(c + d*x**6)), x)

________________________________________________________________________________________